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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2023
  • Medium
  • Numerical

Three point charges \(q,-2 q\) and \(2 q\) are placed on \(x\)-axis at a distance \(x=0, x=\frac{3}{4} R\) and \(x=R\) respectively from origin as shown. If \(q =2 \times 10^{-6}\,C\) and \(R =2\,cm\), the magnitude of net force experienced by the charge \(-2 q\) is .......... \(N\)

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Answer & Solution

Correct Answer

(B) \(5440\)

Step-by-step Solution

Detailed explanation

\(F _{ BA }=\frac{ Kq (2 q )}{\left(\frac{3}{4} R \right)^2}=\frac{32 Kq ^2}{9 R ^2}\)

\(F _{ BC }=\frac{ K (2 q )(2 q )}{\left(\frac{ R }{4}\right)^2}=\frac{64 Kq ^2}{ R ^2}\)

\(F _{ B }= F _{ BC }- F _{ BA }=\frac{544 Kq ^2}{9 R ^2}\)

\(=\frac{544 \times 9 \times 10^9 \times\left(2 \times 10^{-6}\right)^2}{9 \times\left(2 \times 10^{-2}\right)^2}=5440\,N\)

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