JEE Mains · Maths · STD 11 - 8. sequence and series
Let \(S_n\) denote the sum of the first \(n\) terms of an \(A.P\).. If \(S_4 = 16\) and \(S_6 = -48\), then \(S_{10}\) is equal to
- A \(-410\)
- B \(-260\)
- C \(-320\)
- D \(-380\)
Answer & Solution
Correct Answer
(C) \(-320\)
Step-by-step Solution
Detailed explanation
\(2\left\{ {2a + 3d} \right\} = 16\) \(3\left\{ {2a + 5d} \right\} = - 48\) \(2a + 3d = 8\) \(2a + 5d = - 16\) \(d = - 12\) \({S_{10}} = 5\left\{ {44 - 9 \times 12} \right\}\) \( = - 320\)
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