JEE Mains · Maths · STD 12 - 13. probability
Let \(B _{i}(i=1,2,3)\) be three independent events in a sample space. The probability that only \(B _{1}\) occur is \(\alpha,\) only \(B _{2}\) occurs is \(\beta\) and only \(B _{3}\) occurs is \(\gamma\). Let \(p\) be the probability that none of the events \(B _{i}\) occurs and these \(4\) probabilities satisfy the equations \((\alpha-2 \beta) p =\alpha \beta\) and \((\beta-3 \gamma) p =2 \beta \gamma\) (All the probabilities are assumed to lie in the interval \((0,1))\). Then \(\frac{ P \left( B _{1}\right)}{ P \left( B _{3}\right)}\) is equal to ..........
- A \(5\)
- B \(6\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
Let \(P \left( B _{1}\right)= p _{1}, P \left( B _{2}\right)= p _{2}, P \left( B _{3}\right)= p _{3}\) given that \(p _{1}\left(1- p _{2}\right)\left(1- p _{3}\right)=\alpha\) \(.....(i)\) \(p _{2}\left(1- p _{1}\right)\left(1- p _{3}\right)=\beta\) \(....(ii)\)…
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