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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

The magnitude of magnetic induction at mid-point \(O\) due to current arrangement as shown in Fig will be

  1. A \(\frac{\mu_0 I}{2 \pi a }\)
  2. B \(0\)
  3. C \(\frac{\mu_0 I }{4 \pi a }\)
  4. D \(\frac{\mu_0 I}{\pi a }\)
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Answer & Solution

Correct Answer

(D) \(\frac{\mu_0 I}{\pi a }\)

Step-by-step Solution

Detailed explanation

Magnetic field due to current in \(BC\) and \(ET\) are outward at point ' \(O\) ' \(B _0=\frac{\mu_0 i }{4 \pi r }+\frac{\mu_0 i }{4 \pi r }=\frac{\mu_0 i }{2 \pi r }=\frac{\mu_0 i }{\pi a }\)
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