JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
The magnitude of magnetic induction at mid-point \(O\) due to current arrangement as shown in Fig will be

- A \(\frac{\mu_0 I}{2 \pi a }\)
- B \(0\)
- C \(\frac{\mu_0 I }{4 \pi a }\)
- D \(\frac{\mu_0 I}{\pi a }\)
Answer & Solution
Correct Answer
(D) \(\frac{\mu_0 I}{\pi a }\)
Step-by-step Solution
Detailed explanation
Magnetic field due to current in \(BC\) and \(ET\) are outward at point ' \(O\) ' \(B _0=\frac{\mu_0 i }{4 \pi r }+\frac{\mu_0 i }{4 \pi r }=\frac{\mu_0 i }{2 \pi r }=\frac{\mu_0 i }{\pi a }\)
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