Magnetic field in a plane electromagnetic wave is given by B = B0,, ( kx + t) jT Expression for corresponding electric field will be Where c is speed of light

(B) \vec E = \frac{{{B_0}}}{c}\,\sin \,\left( {kx + \omega t} \right)\hat k\,V/m

(C) \vec E = - {B_0}\,c\sin \,\left( {kx + \omega t} \right)\hat k\,V/m

(D) \vec E = {B_0}\,c\sin \,\left( {kx - \omega t} \right)\hat k\,V/m

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JEE Mains · Physics · STD 12 - Electromagnetic waves

JEE Mains 2017
Medium
MCQ

Magnetic field in a plane electromagnetic wave is given by \(\vec B = {B_0}\,\sin \,\left( {kx + \omega t} \right)\hat jT\) Expression for corresponding electric field will be Where \(c\) is speed of light

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Answer & Solution

Correct Answer

(A) \(\vec E = {B_0}\,c\sin \,\left( {kx + \omega t} \right)\hat k\,V/m\)

Step-by-step Solution

Detailed explanation

Speed of \(EM\) wave in force space \(\left( c \right) = \frac{{{E_0}}}{{{B_0}}}\,\)

or \(\vec E = c{B_0}{\mkern 1mu} \sin {\mkern 1mu} \left( {kx + \omega t} \right)\hat k\)

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