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JEE Mains · Physics · STD 11- 8. mechanical properties of solids

The length of wire becomes \(l_1\) and \(l_2\) when \(100\,N\) and \(120\,N\) tensions are applied respectively. If \(10l_2=11l_1\), the natural length of wire will be \(\frac{1}{x} l_1\). Here the value of \(x\) is ........

  1. A \(8\)
  2. B \(2\)
  3. C \(6\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

Let the original length be ' \(\ell_0\) ' When \(T _1=100\,N\), Extension \(=\ell_1-\ell_0\) When \(T _2=120\,N\), Extension \(=\ell_2-\ell_0\) Then \(100= K \left(\ell_1-\ell_0\right)\) And \(120= K \left(\ell_2-\ell_0\right)\)…
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