JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2023
- Hard
- Numerical
For a charged spherical ball, electrostatic potential inside the ball varies with \(r\) as \(V =2 ar ^2+ b\). Here, \(a\) and \(b\) are constant and \(r\) is the distance from the center. The volume charge density inside the ball is \(-\lambda a \varepsilon\). The value of \(\lambda\) is \(...........\). \(\varepsilon=\) permittivity of medium.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(12\)
Step-by-step Solution
Detailed explanation
\(E =-\frac{ dV }{ dr }=-4 ar \equiv \frac{\rho r }{3 \varepsilon_0} \text { (compare) }\)
Result inside uniformly charged solid sphere.
\(\rho=-12 a \varepsilon_0\)
\(\lambda=12\)
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