JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
For a charged spherical ball, electrostatic potential inside the ball varies with \(r\) as \(V =2 ar ^2+ b\). Here, \(a\) and \(b\) are constant and \(r\) is the distance from the center. The volume charge density inside the ball is \(-\lambda a \varepsilon\). The value of \(\lambda\) is \(...........\). \(\varepsilon=\) permittivity of medium.
- A \(11\)
- B \(12\)
- C \(6\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(12\)
Step-by-step Solution
Detailed explanation
\(E =-\frac{ dV }{ dr }=-4 ar \equiv \frac{\rho r }{3 \varepsilon_0} \text { (compare) }\) Result inside uniformly charged solid sphere. \(\rho=-12 a \varepsilon_0\) \(\lambda=12\)
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