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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

For a charged spherical ball, electrostatic potential inside the ball varies with \(r\) as \(V =2 ar ^2+ b\). Here, \(a\) and \(b\) are constant and \(r\) is the distance from the center. The volume charge density inside the ball is \(-\lambda a \varepsilon\). The value of \(\lambda\) is \(...........\). \(\varepsilon=\) permittivity of medium.

  1. A \(11\)
  2. B \(12\)
  3. C \(6\)
  4. D \(3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(12\)

Step-by-step Solution

Detailed explanation

\(E =-\frac{ dV }{ dr }=-4 ar \equiv \frac{\rho r }{3 \varepsilon_0} \text { (compare) }\) Result inside uniformly charged solid sphere. \(\rho=-12 a \varepsilon_0\) \(\lambda=12\)
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