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JEE Mains · Physics · STD 11 - 3.1 vectors

Two forces \(\vec{F}_1\) and \(\vec{F}_2\) are acting on a body. One force has magnitude thrice that of the other force and the resultant of the two forces is equal to the force of larger magnitude. The angle between \(\vec{F}_1\) and \(\overrightarrow{\mathrm{F}}_2\) is \(\cos ^{-1}\left(\frac{1}{\mathrm{n}}\right)\). The value of \(|\mathrm{n}|\) is __________.

  1. A \(6\)
  2. B \(7\)
  3. C \(8\)
  4. D \(9\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(6\)

Step-by-step Solution

Detailed explanation

\(\left|\overrightarrow{\mathrm{F}}_1\right|=\mathrm{F}\) \(\left|\overrightarrow{\mathrm{F}}_{\mathrm{R}}\right|=\left|\overrightarrow{\mathrm{F}}_2\right|=3 \mathrm{~F}\) \(\mathrm{~F}_{\mathrm{R}}^2=\mathrm{F}_1^2+\mathrm{F}_2^2+2 \mathrm{~F}_1 \mathrm{~F}_2 \cos \theta\)…
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