JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A ray of light is incident from air on a glass plate having thickness \(\sqrt{3} \,cm\) and refractive index \(\sqrt{2}\). The angle of incidence of a ray is equal to the critical angle for glass-air interface. The lateral displacement of the ray when it passes through the plate is \(.......\times 10^{-2}\) (given \(\sin 15^{\circ}=0.26\) )
- A \(21\)
- B \(69\)
- C \(50\)
- D \(52\)
Answer & Solution
Correct Answer
(D) \(52\)
Step-by-step Solution
Detailed explanation
\(\sin c=\frac{1}{\sqrt{2}}\) \(c=45^{\circ}\) \(\sin c=\mu \sin \theta\) \(\frac{1}{\sqrt{2}}=\sqrt{2} \sin \theta\) \(\theta=30^{\circ}\) Lateral displacement: \(x=t \sin (i-r) \sec r\) \(x=\sqrt{3} \sin \left(45^{\circ}-30^{\circ}\right) \sec 30^{\circ}\)…
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