A potentiometer wire \(PQ\) of \(1\,m\) length is connected to a standard cell \(E _{1}\). Another cell \(E _{2}\) of emf \(1.02\, V\) is connected with a resistance \('r'\) and switch \(S\) (as shown in figure). With switch \(S\) open, the null position is obtained at a distance of \(49\, cm\) from \(Q\). The potential gradient in the potentiometer wire is.......\(V/cm\)

Pick an option to check your answer.

Verified Solution

Answer & Solution

Correct Answer

(A) \(0.02\)

Step-by-step Solution

Detailed explanation

Sol. Balancing length is measured from \(P.\)

So \(100-49=51 cm\)

\(E _{2}=\phi \times 51\)

Where \(\phi=\) Potential gradient

\(1.02=\phi \times 51\)

\(\phi=0.02 V / cm\)

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