JEE Mains · Physics · STD 11 - 13. oscillations
Two blocks of masses \(m\) and \(M,(M \gt m)\), are placed on a frictionless table as shown in figure. A massless spring with spring constant k is attached with the lower block. If the system is slightly displaced and released then
(\(\mu=\) coefficient of friction between the two blocks)

(A) The time period of small oscillation of the two blocks is \(\mathrm{T}=2 \pi \sqrt{\frac{(\mathrm{~m}+\mathrm{M})}{\mathrm{k}}}\)
(B) The acceleration of the blocks is \(\mathrm{a}=\frac{\mathrm{kx}}{\mathrm{M}+\mathrm{m}}\) (\(\mathrm{x}=\) displacement of the blocks from the mean position)
(C) The magnitude of the frictional force on the upper block is \(\frac{m \mu|x|}{M+m}\)
(D) The maximum amplitude of the upper block, if it does not slip, is \(\frac{\mu(M+m) g}{k}\)
(E) Maximum frictional force can be \(\mu(\mathrm{M}+\mathrm{m}) \mathrm{g}\).
Choose the correct answer from the options given below:
- A A, B, D Only
- B B, C, D Only
- C C, D, E Only
- D A, B, C Only
Answer & Solution
Correct Answer
(A) A, B, D Only
Step-by-step Solution
Detailed explanation
(A) As both blocks moving together so Time period \(=2 \pi \sqrt{\frac{\mathrm{~m}}{\mathrm{~K}}} ;\) where \(\mathrm{m}=\mathrm{M}+\mathrm{m}\) \(\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{M}+\mathrm{m}}{\mathrm{~K}}}\) (B) Let block is displaced by x in \((+\mathrm{ve})\) direction…
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