JEE Mains · Physics · STD 11 - 11. thermodynamics
The given figure represents two isobaric processes for the same mass of an ideal gas, then ....
- A \(P_2 \geq P_1\)
- B \(P_2>P_1\)
- C \(P_1=P_2\)
- D \(P_1>P_2\)
Answer & Solution
Correct Answer
(D) \(P_1>P_2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{PV}=\mathrm{nRT}\) \(\mathrm{V}=\left(\frac{\mathrm{nR}}{\mathrm{P}}\right)_{\mathrm{T}}\) \(\text { Slope }=\frac{\mathrm{nR}}{\mathrm{P}}\) \(\text { Slope } \propto \frac{1}{\mathrm{P}}\) \((\text { Slope })_2>(\text { Slope })_1\) \(\mathrm{P}_2<\mathrm{P}_1\)
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