ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2024
  • Hard
  • MCQ

The given figure represents two isobaric processes for the same mass of an ideal gas, then ....

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(P_1>P_2\)

Step-by-step Solution

Detailed explanation

\(\mathrm{PV}=\mathrm{nRT}\)

\(\mathrm{V}=\left(\frac{\mathrm{nR}}{\mathrm{P}}\right)_{\mathrm{T}}\)

\(\text { Slope }=\frac{\mathrm{nR}}{\mathrm{P}}\)

\(\text { Slope } \propto \frac{1}{\mathrm{P}}\)

\((\text { Slope })_2>(\text { Slope })_1\)

\(\mathrm{P}_2<\mathrm{P}_1\)

Same subject
Explore more questions on app