JEE Mains · Physics · STD 12 - 10. Wave optics
A polarizer - analyser set is adjusted such that the intensity of light coming out of the analyser is just \(10 \%\) of the original intensity. Assuming that the polarizer - analyser set does not absorb any light, the angle by which the analyser need to be rotated further to reduce the output intensity to be zero, is.....\(^o\)
- A \(18.4\)
- B \(71.6\)
- C \(90\)
- D \(45\)
Answer & Solution
Correct Answer
(A) \(18.4\)
Step-by-step Solution
Detailed explanation
\(\frac{I_{0}}{10}=I=\frac{I_{0}}{2} \times \cos ^{2} \theta\) \(\cos \theta=\frac{1}{\sqrt{5}}\) \(\theta=63.44^{\circ}\) angle rotated \(=90-63.44^{\circ}=26.56^{\circ}\) Closest is \(1\)
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