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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2020
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  • MCQ

A polarizer - analyser set is adjusted such that the intensity of light coming out of the analyser is just \(10 \%\) of the original intensity. Assuming that the polarizer - analyser set does not absorb any light, the angle by which the analyser need to be rotated further to reduce the output intensity to be zero, is.....\(^o\)

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Answer & Solution

Correct Answer

(A) \(18.4\)

Step-by-step Solution

Detailed explanation

\(\frac{I_{0}}{10}=I=\frac{I_{0}}{2} \times \cos ^{2} \theta\)

\(\cos \theta=\frac{1}{\sqrt{5}}\)

\(\theta=63.44^{\circ}\)

angle rotated \(=90-63.44^{\circ}=26.56^{\circ}\)

Closest is \(1\)

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