JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A body of mass \(1000 \mathrm{~kg}\) is moving horizontally with a velocity \(6 \mathrm{~m} / \mathrm{s}\). If \(200 \mathrm{~kg}\) extra mass is added, the final velocity (in \(\mathrm{m} / \mathrm{s}\) ) is:
- A \(6\)
- B \(2\)
- C \(3\)
- D \(5\)
Answer & Solution
Correct Answer
(D) \(5\)
Step-by-step Solution
Detailed explanation
Momentum will remain conserve \( 1000 \times 6=1200 \times v \) \( v=5 \mathrm{~m} / \mathrm{s}\)
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