Two light waves having the same wavelength \(\lambda\) in vacuum are in phase initially. Then the first wave travels a path \(L _{1}\) through a medium of refractive index \(n_{1}\) while the second wave travels a path of length \(L_{2}\) through a medium of refractive index \(n _{2}\). After this the phase difference between the two waves is:

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Answer & Solution

Correct Answer

(A) \(\frac{2 \pi}{\lambda}\left( n _{1} L _{1}- n _{2} L _{2}\right)\)

Step-by-step Solution

Detailed explanation

\(\Delta p = n _{1} L _{1}- n _{2} L _{2}\)

\(\Delta \phi=\frac{2 \pi}{\lambda} \Delta p\)

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