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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2022
  • Hard
  • Numerical

The equivalent capacitance between points \(A\) and \(B\) in below shown figure will be..........\(\mu F\).

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Answer & Solution

Correct Answer

(C) \(6\)

Step-by-step Solution

Detailed explanation

Two capacitors are short circuited

Finally equivalent capacitance

\(=\frac{24 \times 8}{24+8}=\frac{24 \times 8}{32}=6 \mu F\)

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