JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
The equivalent capacitance between points \(A\) and \(B\) in below shown figure will be..........\(\mu F\).
- A \(9\)
- B \(60\)
- C \(6\)
- D \(79\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
Two capacitors are short circuited Finally equivalent capacitance \(=\frac{24 \times 8}{24+8}=\frac{24 \times 8}{32}=6 \mu F\)
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