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JEE Mains · Maths · STD 12 - 2. inverse trigonometric function

\(\sin ^{-1}\left(\sin \frac{2 \pi}{3}\right)+\cos ^{-1}\left(\cos \frac{7 \pi}{6}\right)+\tan ^{-1}\left(\tan \frac{3 \pi}{4}\right) \quad\) is equal to

  1. A \(\frac{31 \pi}{12}\)
  2. B \(\frac{17 \pi}{12}\)
  3. C \(\frac{11 \pi}{12}\)
  4. D \(-\frac{3 \pi}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{11 \pi}{12}\)

Step-by-step Solution

Detailed explanation

\(\sin ^{-1}\left(\sin \frac{2 \pi}{3}\right)+\cos ^{-1}\left(\cos \frac{7 \pi}{6}\right)+\tan ^{-1} \tan \left(\frac{3 \pi}{4}\right)\) \(\sin ^{-1} \sin \left(\frac{2 \pi}{3}\right)=\pi-\frac{2 \pi}{3}=\frac{\pi}{3}\)…
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