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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2022
  • Hard
  • MCQ

The electric field at the point associated with a light wave is given by \(E=200\left[\sin \left(6 \times 10^{15}\right) t+\sin \left(9 \times 10^{15}\right) t\right] \,Vm ^{-1}\) Given : \(h=4.14 \times 10^{-15} \,eVs\) If this light falls on a metal surface having a work function of \(2.50 \,eV\), the maximum kinetic energy of the photoelectrons will be ........... \(eV\)

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Answer & Solution

Correct Answer

(D) \(3.42\)

Step-by-step Solution

Detailed explanation

For maximum \(KE\) we will take higher frequency \(\left(f=\frac{9 \times 10^{15}}{2 \pi} Hz \right)\)

\(K_{\max }=h f-\phi\)

\(=\frac{9 \times 10^{15} \times 4.14 \times 10^{-15}}{2 \pi}-2.50\)

\(3.43 \,eV\)

nearest is \(3.42 \,eV\)

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