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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The electric field at the point associated with a light wave is given by \(E=200\left[\sin \left(6 \times 10^{15}\right) t+\sin \left(9 \times 10^{15}\right) t\right] \,Vm ^{-1}\) Given : \(h=4.14 \times 10^{-15} \,eVs\) If this light falls on a metal surface having a work function of \(2.50 \,eV\), the maximum kinetic energy of the photoelectrons will be ........... \(eV\)
- A \(1.90\)
- B \(3.27\)
- C \(3.60\)
- D \(3.42\)
Answer & Solution
Correct Answer
(D) \(3.42\)
Step-by-step Solution
Detailed explanation
For maximum \(KE\) we will take higher frequency \(\left(f=\frac{9 \times 10^{15}}{2 \pi} Hz \right)\) \(K_{\max }=h f-\phi\) \(=\frac{9 \times 10^{15} \times 4.14 \times 10^{-15}}{2 \pi}-2.50\) \(3.43 \,eV\) nearest is \(3.42 \,eV\)
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