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JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2013
- Hard
- MCQ
If the ratio of lengths, radii and Young's moduli of steel and brass wires in the figure are \(a, b\) and \(c\) respectively, then the corresponding ratio of increase in their lengths is

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Answer & Solution
Correct Answer
(C) \(\frac{{3a}}{{2{b^2}c}}\)
Step-by-step Solution
Detailed explanation
According to questions,
\(\frac{{{\ell _s}}}{{{\ell _b}}} = a,\frac{{{r_s}}}{{{r_b}}} = b,\frac{{{y_s}}}{{{y_b}}} = c,\frac{{\Delta \ell s}}{{\Delta {\ell _b}}} = ?\)
\(As,y = \frac{{F\ell }}{{A\Delta \ell }} \Rightarrow \Delta \ell = \frac{{F\ell }}{{Ay}}\)
\(\Delta {\ell _s} = \frac{{3mg{\ell _s}}}{{\pi _s^2.{y_s}}}\left[ {{F_s} = \left( {M + 2M} \right)g} \right]\)
\(\Delta {\ell _b} = \frac{{2Mg{\ell _b}}}{{\pi r_b^2{y_b}}}\left[ {{F_b} = 2Mg} \right]\)
\(\therefore \frac{{\Delta {\ell _s}}}{{\Delta {\ell _b}}} = \frac{{\frac{{3Mg{\ell _s}}}{{\pi r_s^2.{y_s}}}}}{{\frac{{2Mg.{\ell _b}}}{{\pi {b^2}.{y_b}}}}} = \frac{{3a}}{{2{b^2}C}}\)
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