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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2026
  • Hard
  • MCQ

The de Broglie wavelength of an oxygen molecule at \(27^{\circ} C\) is \(x \times 10^{-12} m\). The value of \(x\) is (take Planck's constant \(=6.63 \times 10^{-34} J . s\), Boltzmann constant \(=1.38 \times 10^{-23} J / K\), mass of oxygen. Molecule \(\left.=5.31 \times 10^{-26} kg\right)\).

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Answer & Solution

Correct Answer

(A) 26

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Detailed explanation

\( \lambda=\frac{h}{\sqrt{2mK}}=\frac{h}{\sqrt{2m(\frac{3}{2}kT)}} \)
\( \lambda=\frac{h}{\sqrt{3mkT}} \)
\( =\frac{6.63\times10^{-34}}{\sqrt{3\times5.31\times10^{-26}\times1.38\times10^{-23}\times300}} \)
\( =2.58\times10^{-11}=25.8\times10^{-12} \)
So, \( x=26 \)
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