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JEE Mains · Physics · STD 12 - 1. Electric charges and fields
In finding the electric field using Gauss Law the formula \(|\overrightarrow{\mathrm{E}}|=\frac{q_{\mathrm{enc}}}{\varepsilon_{0}|\mathrm{A}|}\) is applicable. In the formula \(\varepsilon_{0}\) is permittivity of free space, \(A\) is the area of Gaussian surface and \(q_{enc}\) is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
- A Only when the Gaussian surface is an equipotential surface
- B Only when \(|\overrightarrow{\mathrm{E}}|=\) constant on the surface.
- C For any choice of Gaussian surface.
- D Only when the Gaussian surface is an equipotential surface and \(|\overrightarrow{\mathrm{E}}|\) is constant on the surface.
Answer & Solution
Correct Answer
(D) Only when the Gaussian surface is an equipotential surface and \(|\overrightarrow{\mathrm{E}}|\) is constant on the surface.
Step-by-step Solution
Detailed explanation
\(|\overrightarrow{\mathrm{E}}|\) should be constant on the surface and the surface should be equipotential.
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