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JEE Mains · Physics · STD 12 - Magnetism and matter
  • JEE Mains 2022
  • Easy
  • MCQ

The vertical component of the earth's magnetic field is \(6 \times 10^{-5} T\) at any place where the angle of dip is \(37^{\circ}\). The earth's resultant magnetic field at that place will be \(\left(\right.\) Given \(\left.\tan 37^{\circ}=\frac{3}{4}\right)\)

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Answer & Solution

Correct Answer

(D) \(1 \times 10^{-4}\,T\)

Step-by-step Solution

Detailed explanation

\(\left(\delta=37^{\circ}\right)\)

\(B _{ V }= B \sin \delta\)

\(6 \times 10^{-5}= B \frac{3}{5}\)

\(B =10 \times 10^{-5}\,T\)

\(=10^{-4}\,T\)

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