JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
If force \(\vec{F}=3 \hat{i}+4 \hat{j}-2 \hat{k}\) acts on a particle having position vector \(2 \hat{i}+\hat{j}+2 \hat{k}\) then, the torque about the origin will be
- A \(3 \hat{ i }+4 \hat{ j }-2 \hat{ k }\)
- B \(-10 \hat{ i }+10 \hat{ j }+5 \hat{ k }\)
- C \(10 \hat{ i }+5 \hat{ j }-10 \hat{ k }\)
- D \(10 \hat{ i }+\hat{ j }-5 \hat{ k }\)
Answer & Solution
Correct Answer
(B) \(-10 \hat{ i }+10 \hat{ j }+5 \hat{ k }\)
Step-by-step Solution
Detailed explanation
\(\vec{\tau}=\vec{r} \times \vec{F}\) \(=\left|\begin{array}{ccc}\hat{i} & \hat{j} & \hat{k} \\ 2 & 1 & 2 \\ 3 & 4 & -2\end{array}\right|\) \(=\hat{\hat{i}}(-2-8)-\hat{ j }(-4-6)+\hat{ k }(8-3)\) \(=-10 \hat{ i }+10 \hat{ j }+5 \hat{ k }\)
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