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JEE Mains · Physics · STD 11 - Vectors
  • JEE Mains 2021
  • Hard
  • MCQ

The angle between vector \((\overrightarrow{{A}})\) and \((\overrightarrow{{A}}-\overrightarrow{{B}})\) is :

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Answer & Solution

Correct Answer

(C) \(\tan ^{-1}\left(\frac{\sqrt{3} {B}}{2 {A}-{B}}\right)\)

Step-by-step Solution

Detailed explanation

Angle between \(\overrightarrow{{A}}\) and \(\overrightarrow{{B}}, \theta=60^{\circ}\)

Angle betwenn \(\overrightarrow{{A}}\) and \(\overrightarrow{{A}}-\overrightarrow{{B}}\)

\(\tan \alpha=\frac{B \sin \theta}{A-B \cos \theta}\)

\(=\frac{B \sqrt{\frac{3}{2}}}{A-B \times \frac{1}{2} 2}\)

\(\tan \alpha=\frac{\sqrt{3} B}{2 A-B}\)

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