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JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2022
  • Medium
  • Numerical

The activity of a radioactive material is \(2.56 \times 10^{-3} \,Ci\). If the half life of the material is \(5\) days, after how many days the activity will become \(2 \times 10^{-5} \,Ci\) ?

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Answer & Solution

Correct Answer

(B) \(35\)

Step-by-step Solution

Detailed explanation

\(\frac{ A }{ A _{0}}=\frac{ N }{ N _{0}}\)

\(\frac{2 \times 10^{-5}}{2.56 \times 10^{-3}}=\frac{ N }{ N _{0}}\)

\(\frac{ N }{ N _{0}}=\frac{1}{128} \Rightarrow N =\frac{ N _{0}}{128}\)

After \(7\) half life activity comes down to given value \(T =7 \times 5\) \(=35\) days

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