JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
Consider a light ray travelling in air is incident into a medium of refractive index \(\sqrt{2 n}\). The incident angle is twice that of refracting angle. Then, the angle of incidence will be
- A \(\sin ^{-1}(\sqrt{n})\)
- B \(\cos ^{-1}\left(\sqrt{\frac{n}{2}}\right)\)
- C \(\sin ^{-1}(\sqrt{2 n})\)
- D \(2 \cos ^{-1}\left(\sqrt{\frac{n}{2}}\right)\)
Answer & Solution
Correct Answer
(D) \(2 \cos ^{-1}\left(\sqrt{\frac{n}{2}}\right)\)
Step-by-step Solution
Detailed explanation
\(i=2 r\) \(\sin i \times n_{1}=\sin r \times n_{2}\) \(\sin i \times 1=\sin \frac{i}{2} \times \sqrt{2 n}\) \(\frac{\sin i}{\sin \frac{i}{2}}=\sqrt{2 n}\) \(\frac{\sin \frac{i}{2} \cos \frac{i}{2}}{\sin \frac{i}{2}} \sqrt{2 n}\) \(\cos \frac{i}{2}=\sqrt{\frac{n}{2}}\)…
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