JEE Mains · Physics · STD 12 - 10. Wave optics
Two coherent sources produce waves of different intensities which interfere. After interference, the ratio of the maximum intensity to the minimum intensity is \(16\). The intensity of the waves are in the ratio
- A \(16 : 9\)
- B \(25 : 9\)
- C \(4 : 1\)
- D \(5 : 3\)
Answer & Solution
Correct Answer
(B) \(25 : 9\)
Step-by-step Solution
Detailed explanation
\(\left( {\frac{{\sqrt {{I_1}} + \sqrt {{I_2}} }}{{\sqrt {{I_1}} - \sqrt {{I_2}} }}} \right) = \frac{{16}}{1}\) ; \(\frac{\sqrt{I_{1}}+\sqrt{I_{2}}}{\sqrt{I_{1}}-\sqrt{I_{2}}}=\frac{4}{1}\) \( \Rightarrow \quad 3\sqrt {{I_1}} = 5\sqrt {{I_2}} \)…
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