JEE Mains · Physics · STD 11 - 11. thermodynamics
Match the thermodynamic processes taking place in a system with the correct conditions. In the table: \(\Delta Q\) is the heat supplied, \(\Delta W\) is the work done and \(\Delta U\) is change in internal energy of the system
| Process | Condition |
| \((I)\) Adiabatic | \((A)\; \Delta W =0\) |
| \((II)\) Isothermal | \((B)\; \Delta Q=0\) |
| \((III)\) Isochoric | \((C)\; \Delta U \neq 0, \Delta W \neq 0 \Delta Q \neq 0\) |
| \((IV)\) Isobaric | \((D)\; \Delta U =0\) |
- A \(I-B, II-D, III-A, IV-C\)
- B \(I-B, II-A, III-D, IV-C\)
- C \(I - A , II - A , III - B , IV - C\)
- D \(I - A , II - B , III - D , IV - D\)
Answer & Solution
Correct Answer
(A) \(I-B, II-D, III-A, IV-C\)
Step-by-step Solution
Detailed explanation
\((I)\) Adiabatic process \(\Rightarrow \Delta Q=0\) No exchange of heat takes place with surroundings \((II)\) Isothermal proess \(\Rightarrow\) Temperature remains constant \((\Delta T =0)\) \(\Delta u =\frac{ F }{2} nR \Delta T \Rightarrow \Delta u =0\) No change in internal…
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