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JEE Mains · Physics · STD 11 - 11. thermodynamics

Match the thermodynamic processes taking place in a system with the correct conditions. In the table: \(\Delta Q\) is the heat supplied, \(\Delta W\) is the work done and \(\Delta U\) is change in internal energy of the system
Process Condition
\((I)\) Adiabatic \((A)\; \Delta W =0\)
\((II)\) Isothermal \((B)\; \Delta Q=0\)
\((III)\) Isochoric \((C)\; \Delta U \neq 0, \Delta W \neq 0 \Delta Q \neq 0\)
\((IV)\) Isobaric \((D)\; \Delta U =0\)

  1. A \(I-B, II-D, III-A, IV-C\)
  2. B \(I-B, II-A, III-D, IV-C\)
  3. C \(I - A , II - A , III - B , IV - C\)
  4. D \(I - A , II - B , III - D , IV - D\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(I-B, II-D, III-A, IV-C\)

Step-by-step Solution

Detailed explanation

\((I)\) Adiabatic process \(\Rightarrow \Delta Q=0\) No exchange of heat takes place with surroundings \((II)\) Isothermal proess \(\Rightarrow\) Temperature remains constant \((\Delta T =0)\) \(\Delta u =\frac{ F }{2} nR \Delta T \Rightarrow \Delta u =0\) No change in internal…
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