JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2019
- Medium
- MCQ
The figure shows a Young’s double slit experimental setup. It is observed that when a thin transparent sheet of thickness \(t\) and refractive index \(\mu \) is put in front of one of the slits, the central maximum gets shifted by a distance equal to \(n\) fringe widths. If the wavelength of light used is \(\lambda ,\,t\) will be
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Answer & Solution
Correct Answer
(D) \(\frac{{n\lambda }}{{\left( {\mu - 1} \right)}}\)
Step-by-step Solution
Detailed explanation
Path difference at central maxima \(\Delta x=(\mu-1)\, t,\) whole pattern will shift by same amount which will be given by
\((\mu-1) \,t \frac{D}{d}=n \frac{\lambda D}{d},\) according to eh question \(t=\frac{n \lambda}{(\mu-1)}\)
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\(\therefore \) Correct option should be (Bonus)
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