JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A current carrying rectangular loop PQRS is made of uniform wire. The length \(PR = QS =5\,cm\) and \(PQ = RS =100\,cm\). If ammeter current reading changes from I to \(2 I\), the ratio of magnetic forces per unit length on the wire \(P Q\) due to wire RS in the two cases respectively \(f_{ PQ }^{ I }: f_{ PQ }^{2 I }\) is :

- A \(1: 2\)
- B \(1: 4\)
- C \(1: 5\)
- D \(1: 3\)
Answer & Solution
Correct Answer
(B) \(1: 4\)
Step-by-step Solution
Detailed explanation
\(F \propto I _1 I _2\) \(F _{ I }: F _{2 I }=1: 4\)
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