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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2022
  • Medium
  • Numerical

In a Young's double slit experiment, an angular width of the fringe is \(0.35^{\circ}\) on a screen placed at \(2\,m\) away for particular wavelength of \(450\,nm\). The angular width of the fringe, when whole system is immersed in a medium of refractive index \(7 / 5\), is \(\frac{1}{\alpha}\). The value of \(\alpha\) is ..............

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Answer & Solution

Correct Answer

(B) \(4\)

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Detailed explanation

\(\beta=\frac{0.35 \times 5}{7}=0.25\)

\(\frac{1}{\alpha}=\frac{2.5}{100}\)

\(\alpha=4\)

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