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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2020
  • Medium
  • Numerical

In the given circuit, value of \(Y\) is

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Answer & Solution

Correct Answer

(B) \(0\)

Step-by-step Solution

Detailed explanation

\(Y=\overline{\mathrm{AB}} \cdot \mathrm{A}\)

\(=\overline{\overline{\mathrm{AB}}}+\overline{\mathrm{A}}\)

\(=0+0\)

\(=0\)

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