JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2020
- Medium
- Numerical
The circuit shown below is working as a \(8\; \mathrm{V}\;dc\) regulated voltage source. When \(12 \;\mathrm{V}\) is used as input, the power dissipated (in \(\mathrm{mW}\) ) in each diode is (considering both zener diodes are identical)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(40\)
Step-by-step Solution
Detailed explanation
Current in circuit \(=\frac{4}{400}=\frac{1}{100} \mathrm{A}\)
So power dissipited in each diode \(=\) \(\mathrm{VI}\)
\(=4 \times \frac{1}{100} \;\mathrm{W}\)
\(=40 \times 10^{-3}\; \mathrm{mW}\)
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