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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2020
  • Medium
  • Numerical

The circuit shown below is working as a \(8\; \mathrm{V}\;dc\) regulated voltage source. When \(12 \;\mathrm{V}\) is used as input, the power dissipated (in \(\mathrm{mW}\) ) in each diode is (considering both zener diodes are identical)

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Answer & Solution

Correct Answer

(D) \(40\)

Step-by-step Solution

Detailed explanation

Current in circuit \(=\frac{4}{400}=\frac{1}{100} \mathrm{A}\)

So power dissipited in each diode \(=\) \(\mathrm{VI}\)

\(=4 \times \frac{1}{100} \;\mathrm{W}\)

\(=40 \times 10^{-3}\; \mathrm{mW}\)

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