ExamBro
ExamBro
JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2023
  • Medium
  • Numerical

In the circuit shown in the figure, the ratio of the quality factor and the band width is \(.............\) s.

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(A) \(10\)

Step-by-step Solution

Detailed explanation

\(\Delta \omega=\frac{ R }{ L }\)

\(Q =\frac{\omega_0}{\Delta \omega}=\omega_0 \frac{ L }{ R }\)

\(\omega_0=\frac{1}{\sqrt{3 \times 27 \times 10^{-6}}}=\frac{1}{9 \times 10^{-3}}\)

\(\frac{ Q }{\Delta \omega}=\frac{\omega_0 \frac{ L }{ R }}{\frac{ R }{ L }}=\omega_0 \frac{ L ^2}{ R ^2}=\sqrt{\frac{1}{ LC } \frac{ L ^2}{ R ^2}}\)

\(=\frac{1}{9 \times 10^{-3}} \times \frac{9}{100}=10\,s\)

Same subject
Explore more questions on app