JEE Mains · Physics · STD 12 -7. Alternating current
In the circuit shown in the figure, the ratio of the quality factor and the band width is \(.............\) s.
- A \(10\)
- B \(0.1\)
- C \(6\)
- D \(8\)
Answer & Solution
Correct Answer
(A) \(10\)
Step-by-step Solution
Detailed explanation
\(\Delta \omega=\frac{ R }{ L }\) \(Q =\frac{\omega_0}{\Delta \omega}=\omega_0 \frac{ L }{ R }\) \(\omega_0=\frac{1}{\sqrt{3 \times 27 \times 10^{-6}}}=\frac{1}{9 \times 10^{-3}}\)…
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