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JEE Mains · Physics · STD 12 -Electromagnetic induction
  • JEE Mains 2021
  • Hard
  • MCQ

The current \((i)\) at time \(t =0\) and \(t =\infty\) respectively for the given circuit is

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Answer & Solution

Correct Answer

(D) \(\frac{5 E }{18}, \frac{10 E }{33}\)

Step-by-step Solution

Detailed explanation

At \(t=0,\) current through inductor is zero,

hence \(R _{ eq }=(5+1) \|(5+4)=\frac{18}{5}\)

\(i _{1}=\frac{ E }{18 / 5}=\frac{5 E }{18}\)

At \(t=\infty\), inductor becomes a simple wire and now the circuit will be as shown in figure

hence \(R _{ eq }=(5 \| 5)+(4 \| 1)=\frac{33}{10} ; \quad(\| \Rightarrow\) parallel \()\)

\(i _{2}=\frac{ E }{33 / 10}=\frac{10 E }{33}\)

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