JEE Mains · Physics · STD 12 -6. Electromagnetic induction
At time \(\mathrm{t}=0\) magnetic field of \(1000\) Gauss is passing perpendicularly through the area defined by the closed loop shown in the figure. If the magnetic field reduces linearly to \(500\) Gauss, in the next \(5 \;\mathrm{s}\), then induced \(EMF\) in the loop is ........\( \mu \mathrm{V}\)
- A \(36\)
- B \(48\)
- C \(56\)
- D \(28\)
Answer & Solution
Correct Answer
(C) \(56\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{dB}}{\mathrm{dt}}=100\) \(A=16 \times 4-4 \times 2=56 \mathrm{cm}^{2}\) \(\varepsilon=\frac{\mathrm{d} \mathrm{B}}{\mathrm{dt}} \mathrm{A}=100 \times 10^{-4} \times 56 \times 10^{-4}\)
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