JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
A Zener diode of breakdown voltage \(10 \mathrm{~V}\) is used as a voltage regulator as shown in the figure. The current through the Zener diode is _______.

- A \(50 \mathrm{~mA}\)
- B \(0\)
- C \(30 \mathrm{~mA}\)
- D \(20 \mathrm{~mA}\)
Answer & Solution
Correct Answer
(C) \(30 \mathrm{~mA}\)
Step-by-step Solution
Detailed explanation
Zener is in breakdown region. \( I_3=\frac{10}{500}=\frac{1}{50} \) \( I_1=\frac{10}{200}=\frac{1}{20} \) \( I_2=I_1-I_3 \) \( I_2=\left(\frac{1}{20}-\frac{1}{50}\right)=\left(\frac{3}{100}\right)=30 \ m A\)
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