JEE Mains · Physics · STD 12 - 1. Electric charges and fields
Consider a sphere of radius \(\mathrm{R}\) which carries a uniform charge density \(\rho .\) If a sphere of radius \(\frac{\mathrm{R}}{2}\) is carved out of it, as shown, the ratio \(\frac{\left|\overrightarrow{\mathrm{E}}_{\mathrm{A}}\right|}{\left|\overrightarrow{\mathrm{E}}_{\mathrm{B}}\right|}\) of magnitude of electric field \(\overrightarrow{\mathrm{E}}_{\mathrm{A}}\) and \(\overrightarrow{\mathrm{E}}_{\mathrm{B}}\) respectively, at points \(\mathrm{A}\) and \(\mathrm{B}\) due to the remaining portion is

- A \(\frac{18}{54}\)
- B \(\frac{21}{34}\)
- C \(\frac{17}{54}\)
- D \(\frac{18}{34}\)
Answer & Solution
Correct Answer
(D) \(\frac{18}{34}\)
Step-by-step Solution
Detailed explanation
Fill the empty space with \(+\rho\) and \(-\rho\) charge density.…
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