JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Two blocks of masses \(2\) kg and \(1\) kg respectively, are tied to the ends of a string which passes over a light frictionless pulley as shown in the figure below. The masses are held at rest at the same horizontal level and then released. The distance traversed by the centre of mass in \(2\) s is _______ m. (Take \(g = 10\) m/s\(^2\))
- A \(3.33\)
- B \(3.12\)
- C \(2.22\)
- D \(1.42\)
Answer & Solution
Correct Answer
(C) \(2.22\)
Step-by-step Solution
Detailed explanation
The acceleration of the blocks in the Atwood machine is given by: \(a = \dfrac{m_1 - m_2}{m_1 + m_2} g\) Substituting the given values (\(m_1 = 2\) kg, \(m_2 = 1\) kg): \(a = \dfrac{2 - 1}{2 + 1} g = \dfrac{g}{3}\) Taking the downward direction as positive, the acceleration of…
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