JEE Mains · Physics · STD 12 - 12. atoms
In Bohr's atomic model, the electron is assumed to revolve in a circular orbit of radius \(0.5 \times 10^{-10}\,m\). If the speed of electron is \(2.2 \times 10^{6} \;{m} / {s}\), then the current associated with the electron will be \(....\,\times 10^{-2} \;{mA}\). [Take \(\pi\) as \(\left.\frac{22}{7}\right]\)
- A \(112\)
- B \(224\)
- C \(336\)
- D \(741\)
Answer & Solution
Correct Answer
(A) \(112\)
Step-by-step Solution
Detailed explanation
time taken \(=\frac{2 \pi r }{\text { speed }}\) \(=\frac{2 \times \pi \times 5 \times 10^{-11}}{2.2 \times 10^{6}}\) \(=\frac{2 \times 22 \times 10 \times 5 \times 10^{-11}}{7 \times 22 \times 10^{6}}\) \(=\frac{10}{7} \times 10^{-16}\) Current…
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