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JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2021
  • Hard
  • Numerical

In Bohr's atomic model, the electron is assumed to revolve in a circular orbit of radius \(0.5 \times 10^{-10}\,m\). If the speed of electron is \(2.2 \times 10^{6} \;{m} / {s}\), then the current associated with the electron will be \(....\,\times 10^{-2} \;{mA}\). [Take \(\pi\) as \(\left.\frac{22}{7}\right]\)

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Answer & Solution

Correct Answer

(A) \(112\)

Step-by-step Solution

Detailed explanation

time taken \(=\frac{2 \pi r }{\text { speed }}\)

\(=\frac{2 \times \pi \times 5 \times 10^{-11}}{2.2 \times 10^{6}}\)

\(=\frac{2 \times 22 \times 10 \times 5 \times 10^{-11}}{7 \times 22 \times 10^{6}}\)

\(=\frac{10}{7} \times 10^{-16}\)

Current \(\frac{ q }{ t }\left(1 e =1.6 \times 10^{-19} C \right)\)

\(=\frac{1.6 \times 10^{-19}}{10 \times 10^{-16}} \times 7\)

\(=\frac{1.6}{100} \times 10^{-3} \times 7\)

\(=112 \times 10^{-5} A\)

\(=112 \times 10^{-5} \times 1000 m A\)

\(=1.12 mA\)

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