JEE Mains · Maths · STD 12 - 1. relation and function
Let \(A=\{1,3,7,9,11\}\) and \(B=\{2,4,5,7,8,10,12\}\). Then the total number of one-one maps \(\mathrm{f}: \mathrm{A} \rightarrow \mathrm{B}\), such that \(\mathrm{f}(1)+\mathrm{f}(3)=14\), is :
- A \(180\)
- B \(120\)
- C \(480\)
- D \(240\)
Answer & Solution
Correct Answer
(D) \(240\)
Step-by-step Solution
Detailed explanation
\( A=\{1,3,7,9,11\} \) \( B=\{2,4,5,7,8,10,12\} \) \( f(1)+f(3)=14 \) \( \text { (i) } 2+12 \) \( \text { (ii) } 4+10 \) \( 2 \times(2 \times 5 \times 4 \times 3)=240\)
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