JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
Least count of a vernier caliper is \(\frac{1}{20 \mathrm{~N}} \mathrm{~cm}\). The value of one division on the main scale is \(1 \mathrm{~mm}\). Then the number of divisions of main scale that coincide with \(\mathrm{N}\) divisions of vernier scale is _______.
- A \(\left(\frac{2 \mathrm{~N}-1}{20 \mathrm{~N}}\right)\)
- B \(\left(\frac{2 \mathrm{~N}-1}{2}\right)\)
- C \((2 \mathrm{~N}-1)\)
- D \(\left(\frac{2 \mathrm{~N}-1}{2 \mathrm{~N}}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{2 \mathrm{~N}-1}{2}\right)\)
Step-by-step Solution
Detailed explanation
Least count of vernier calipers \(=\frac{1}{20 \mathrm{~N}} \mathrm{~cm}\) \(\because\) Least count\(=1 \mathrm{MSD}-1 \mathrm{VSD}\) let \(\mathrm{x}\) no. of divisions of main scale coincides with \(\mathrm{N}\) division of vernier scale, then…
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