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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
Three straight parallel current carrying conductors are shown in the figure. The force experienced by the middle conductor of length \(25\,cm\) is
- A \(3\times10^{-4}\, N\) toward right
- B \(6\times10^{-4}\, N\) toward right
- C \(9\times10^{-4}\, N\) toward right
- D Zero
Answer & Solution
Correct Answer
(A) \(3\times10^{-4}\, N\) toward right
Step-by-step Solution
Detailed explanation
Also given; length of wire \(Q\) \(=25\, \mathrm{cm}=0.25 \,\mathrm{m}\) Force on wire \(Q\) due to wire \(R\) \(F_{\mathrm{QR}}=10^{-7} \times \frac{2 \times 20 \times 10}{0.05} \times 0.25\) \(=20 \times 10^{-5} \,\mathrm{N}\) (Towards left) Force on wire \(Q\) due to wire…
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