JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
In a system two particles of masses \(m_1=3 \mathrm{~kg}\) and \(\mathrm{m}_2=2 \mathrm{~kg}\) are placed at certain distance from each other. The particle of mass \(m_1\) is moved towards the center of mass of the system through a distance \(2 \mathrm{~cm}\). In order to keep the center of mass of the system at the original position, the particle of mass \(\mathrm{m}_2\) should move towards the center of mass by the distance _______\(\mathrm{cm}\).
- A \(5\)
- B \(4\)
- C \(6\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
\(\Delta \mathrm{X}_{\text {C.O.M }}=\frac{\mathrm{m}_1 \Delta \mathrm{x}_1+\mathrm{m}_2 \Delta \mathrm{x}_2}{\mathrm{~m}_1+\mathrm{m}_2}\) \(\Rightarrow 0=\frac{3 \times 2+2(-\mathrm{x})}{3+2}\) \(\Rightarrow \mathrm{x}=3 \mathrm{~cm}\)
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