JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
In a simple pendulum experiment for determination of acceleration due to gravity \((g)\), time taken for \(20\) oscillations is measured by using a watch of \(1\, second\) least count. The mean value of time taken comes out to be \(30\,s\). The length of pendulum is measured by using a meter scale of least count \(1\, mm\) and the value obtained is \(55.0\, cm\). The percentage error in the determination of \(g\) is close to ........... \(\%\)
- A \(0.7\)
- B \(3.5\)
- C \(6.8\)
- D \(0.2\)
Answer & Solution
Correct Answer
(C) \(6.8\)
Step-by-step Solution
Detailed explanation
\begin{array}{l} T = \frac{{30\,\sec }}{{20}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\Delta T = \frac{1}{{20}}\sec ,\\ \,\,\,\,\,\,\,L = 55\,cm\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\Delta L = 1\,mm = 0.1\,cm\\ \,\,\,\,\,\,\,g = \frac{{4{\pi ^2}L}}{{{T^2}}}\\…
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