JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The diameter of a sphere is measured using a vernier caliper whose \(9\) divisions of main scale are equal to \(10\) divisions of vernier scale. The shortest division on the main scale is equal to \(1 \mathrm{~mm}\). The main scale reading is \(2 \mathrm{~cm}\) and second division of vernier scale coincides with a division on main scale. If mass of the sphere is \(8.635 \mathrm{~g}\), thedensity of the sphere \(1 \mathrm{~s}\) _______.
- A \(2.5 \mathrm{~g} / \mathrm{cm}^3\)
- B \(1.7 \mathrm{~g} / \mathrm{cm}^3\)
- C \(2.2 \mathrm{~g} / \mathrm{cm}^3\)
- D \(2.0 \mathrm{~g} / \mathrm{cm}^3\)
Answer & Solution
Correct Answer
(D) \(2.0 \mathrm{~g} / \mathrm{cm}^3\)
Step-by-step Solution
Detailed explanation
\(\text { Given } 9 \mathrm{MSD}=10 \mathrm{VSD}\) \(\text { mass }=8.635 \mathrm{~g}\) \(\mathrm{LC}=1 \mathrm{MSD}-1 \mathrm{VSD}\) \(\mathrm{LC}=1 \mathrm{MSD}-\frac{9}{10} \mathrm{MSD}\) \(\mathrm{LC}=\frac{1}{10} \mathrm{MSD}\) \(\mathrm{LC}=0.01 \mathrm{~cm}\)…
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