JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
In \(SI\, units\), the dimensions of \(\sqrt {\frac{{{ \varepsilon _0}}}{{{\mu _0}}}} \) is
- A \(A{T^{ - 3}}M{L^{3/2}}\)
- B \({A^{ - 1}}TM{L^3}\)
- C \({A^2}{T^3}{M^{ - 1}}{L^{ - 2}}\)
- D \(A{T^2}{M^{ - 1}}{L^{ - 1}}\)
Answer & Solution
Correct Answer
(C) \({A^2}{T^3}{M^{ - 1}}{L^{ - 2}}\)
Step-by-step Solution
Detailed explanation
\begin{array}{l} Dimension\,of\,\sqrt {\frac{{{\varepsilon _0}}}{{{\mu _0}}}} \\ \left[ {{\varepsilon _0}} \right] = \left[ {{M^{ - 1}}{L^{ - 3}}{T^4}{A^2}} \right]\\ \left[ {{\mu _0}} \right] = \left[ {ML{T^{ - 2}}{A^{ - 2}}} \right]\\ Dimension\,of\,\,\sqrt…
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