JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
It is found that if a neutron suffers an elastic collinear collision with deuterium at rest, fractional loss of its energy is \(p_d \) ; while for its similar collision with carbon nucleus at rest, fractional loss of energy is \(P_c\). The values of \(P_d\) and \(P_c\) are respectively
- A \((0.28,0.89)\)
- B \((0,0)\)
- C \((0,1)\)
- D \((0.89,0.28)\)
Answer & Solution
Correct Answer
(D) \((0.89,0.28)\)
Step-by-step Solution
Detailed explanation
For collision of a nenutron with deuterium \(:\) Applying conservation of momentum\(:\) \(m v+0=m v_{1}+2 m v_{2} \dots(i)\) \(v_{2}-v_{1}=v \ldots(ii)\) Therefore, Collision is elastic, \(e=1\) From equ \((i)\) and equ \((ii)\) \(v_{1}=-v / 3\)…
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