A disc with a flat small bottom beaker placed on it at a distance \(R\) from its center is revolving about an axis passing through the center and perpendicular to its plane with an angular velocity \(\omega\). The coefficient of static friction between the bottom of the beaker and the surface of the disc is \(\mu\). The beaker will revolve with the disc if

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Answer & Solution

Correct Answer

(B) \(R \leq \frac{\mu g }{\omega^{2}}\)

Step-by-step Solution

Detailed explanation

\(f_{s}=m \omega^{2} R\)

We know that \(f_{ S } \leq f _{\text {smax }}\)

\(m \omega^{2} R \leq \mu m g\)

\(R \leq \frac{\mu g }{\omega^{2}}\)

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