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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2022
  • Easy
  • Numerical

Eight copper wire of length \(l\) and diameter \(d\) are joined in parallel to form a single composite conductor of resistance \(R\). If a single copper wire of length \(2\,l\) have the same resistance \((R)\) then its diameter will be \(.....d\).

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Answer & Solution

Correct Answer

(B) \(4\)

Step-by-step Solution

Detailed explanation

Each wire has resistance \(=\rho \frac{4 \ell}{\pi d ^{2}}=r\)

Eight wire in parallel, then equivalent resistance is \(\frac{ r }{8}=\frac{\rho \ell}{2 \pi d ^{2}}\)

Single copper wire of length \(2 l\) has resistance

\(R =\rho \frac{2 \ell \times 4}{\pi d _{1}^{2}}=\frac{\rho \ell}{2 \pi d ^{2}}\)

\(d _{1}=4 d\)

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